O.J. Howard Could Be 2019 Fantasy Football Breakout Due to One Intriguing Stat

Zach Brunner
Tampa Bay Buccaneers v Buffalo Bills
Tampa Bay Buccaneers v Buffalo Bills / Tom Szczerbowski/Getty Images

The tight end position in fantasy football looks strong this year, even with Rob Gronkowski's retirement. With so many solid options, tight end is no longer a position to punt on.

However, if you miss out on the top-tier TEs this season, O.J. Howard could be a solid target, as one stat indicates that he could be in for a breakout year.

Last season, Howard proved to be the most consistent TE at producing quality starts. A quality start for the TE position has been defined as at least 6.5 points in standard scoring. Howard was able to do this in a league-high 70 percent of his games played in 2018.

Zach Ertz and George Kittle were just behind Howard, at 69 percent, Evan Engram did it 64 percent of the time, while Eric Ebron and Travis Kelce tied for fourth, at 63 percent.

After this group, no tight end was able produce quality starts more than half of the time, which helps separate the top-tier tight ends from the less reliable players at the position.

Howard is especially intriguing, though, as he is being drafted as TE4 (57 overall), according to FantasyPros' ADP Rankings. He has the chance to improve in his fourth year in the NFL, especially with Bruce Arians now running the show in Tampa Bay.

Additionally, Howard missed six games in 2018, and if he can stay healthy, a true breakout season could be on the way.

While Howard may not produce quite like Kittle, Kelce and Ertz can, his consistency on a week-to-week basis makes him a worthy consolation prize.

Join FanDuel Sportsbook Today. New users get a risk-free bet up to $500. Join Now.