Cover Photo: Joe Robbins/Getty Images


Aaron Rodgers and Tom Brady will go down as two of the greatest quarterbacks in NFL history, and which of the two is better will be a debate that will rage on for many years. 


However, which of the two signal-callers are the better fantasy option this weekend may not be as hard of a decision to make. 


Strictly from a matchup standpoint, Rodgers is the better start of the two quarterbacks. New England's defense has allowed the 8th-most fantasy points to quarterbacks this year and has allowed opposing quarterbacks to throw for at least 300 yards in four of their eight games this season, including three in their previous three games before Derek Anderson and the Bills put up a dud on Monday night. 

The four quarterbacks who tore the Pats' secondary apart were Patrick Mahomes, Andrew Luck, Mitch Trubisky and Blake Bortles. You could give New England a mulligan on Mahomes, Luck and maybe Trubisky based on how he's playing lately. However, when someone as bad as Blake Bortles is capable of tearing the Pats apart, you have to like Rodgers' chances of teeing off.


Of course, the Pats defense scored a touchdown against the Bills and looked like a top unit on Monday night, but the Bills offense is terrible and was being led by a proven bad QB in Anderson. 

​​Brady has shown that he's matchup-proof, and seems bound to be in for a good game against the Packers' secondary. However, based on his matchup alone, Rodgers may end up outproducing his counterpart once it's all said and done. 


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Mike Esposito is not a FanDuel employee. In addition to providing DFS gameplay advice, Mike Esposito also participates in DFS contests on FanDuel using his personal account, username espo6891. While the strategies and player selections recommended in his articles are his personal views, he may deploy different strategies and player selections when entering contests with his personal account. The views expressed in their articles are the author's alone and do not necessarily reflect the views of FanDuel.